相关疑难解决方法(0)

假设您有一个基本Employee类:

class Employee
{
   public string Name;
   public int Years;
   public string Department;
}

然后(在一个单独的类中)我有以下代码片段(我想我理解除了最后一个):

我相信下面的代码片段是有效的,因为数组initiliser创建了一个Employee对象数组,它们与分配给的workforce变量的类型相同.

Employee[] workforceOne = new Employee[] {
   new Employee() { Name = "David", Years = 0, Department = "software" },
   new Employee() { Name = "Dexter", Years = 3, Department = "software" },
   new Employee() { Name = "Paul", Years = 4, Department = "software" } };

然后我有以下代码片段.我相信这是有效的,因为Employee对象数组的含义是实现的Array()类的实现IEnumerable.因此,我相信这就是为什么数组可以分配给IEnumerable？

IEnumerable workforceTwo = new Employee[] {
   new Employee() { Name = …

有人可以澄清一下C#is关键字.特别是这两个问题:

Q1)第5行; 为什么这会回归真实？

Q2)第7行; 为什么没有施放异常？

public void Test()
{
    object intArray = new int[] { -100, -200 };            

    if (intArray is uint[]) //why does this return true?
    {
        uint[] uintArray = (uint[])intArray; //why no class cast exception?

        for (int x = 0; x < uintArray.Length; x++)
        {
            Console.Out.WriteLine(uintArray[x]);
        }
    }
}

MSDN的描述并未澄清情况.它声明is如果满足其中任何一个条件,它将返回true.(http://msdn.microsoft.com/en-us/library/scekt9xw(VS.71).aspx>MDSN文章)

expression is not null.
expression can be cast to type.

我不相信你可以对int []进行有效的转换为uint [].因为:

A)此代码无法编译:

int[] signed = new int[] { -100 };
uint[] unsigned …