library("tm")
library("NLP")
library("dplyr")
library("readtext")
library("readxl")
library("foreach")
library("devtools")
library("RDCOMClient")
library("rlist")
WDF = vector()
OutApp <- COMCreate("Outlook.Application")
outlookNameSpace = OutApp$GetNameSpace("MAPI")
folderName = "Folder Name"
fld <- outlookNameSpace$GetDefaultFolder(6)
fld = fld$folders(folderName)
Cnt = fld$Items()$Count()
emails <- fld$items
df = data.frame(sno = 1:Cnt,Text = "",stringsAsFactors=FALSE)
for(i in 1:10){
d = as.data.frame(emails(i)$Body(), stringsAsFactors=FALSE)
df$Text[i] = d[1]
df$Sender[i] = emails(i)[['SenderName']]
df$To[i] = emails(i)[['To']]
df$sub[i] = emails(i)[['subject']]
}
emails(2)[['SenderName']]
Run Code Online (Sandbox Code Playgroud)
我正在尝试使用以下代码获取发件人电子邮件地址:
emails(2)[['SenderEmailAddress']]
Run Code Online (Sandbox Code Playgroud)
但它最终给出了这样的:
[1] "/O=EXCHANGELABS/OU=EXCHANGE ADMINISTRATIVE GROUP (FYDIBOHF23SPDLT)/CN=RECIPIENTS/CN=E4CD239AB9F44AC4AC0A4015B6F4805A-RATINGSDIRE"
Run Code Online (Sandbox Code Playgroud) 我使用以下代码提取主题、接收日期和发件人姓名:
Set InboxSelect = GetObject("", "Outlook.Application").GetNamespace("MAPI").PickFolder
i = 0: EmailCount = 0
EmailCount = InboxSelect.Items.Count
While i < EmailCount
i = i + 1
blastRow = Cells(Rows.Count, 1).End(xlUp).Offset(1).Row
LastRow = Sheets("Body").Cells(Rows.Count, 1).End(xlUp).Offset(1).Row
With InboxSelect.Items(i)
MsgBox (SenderEmailAddress)
'If .senderemailaddress = "*@somethingSpecific.co.uk" Then
'EmailCount = EmailCount + 1
Sheets("Import Data").Range("A" & blastRow).Formula = .SenderName
Sheets("Import Data").Range("B" & blastRow).Formula = Format(.ReceivedTime, "dd/mm/yyyy")
Sheets("Import Data").Range("C" & blastRow).Formula = .Subject
Sheets("Body").Range("A" & LastRow).Formula = .Body
'End If
End With
Wend
Run Code Online (Sandbox Code Playgroud)
我现在想要实现的是一个 if 语句,它会说“如果发件人的电子邮件地址是 'anything@somethingSpecific.co.uk',则执行该代码。我已经尝试过 SenderEmailAddress,但在消息中测试时它返回空白盒子。 …