相关疑难解决方法(0)

java.lang.IllegalArgumentException:名为[X]和[Y]的servlet都映射到不允许的url-pattern [/ url]

我试着添加这个servlet

package com.classmgt.servlet;

@WebServlet("/ControllerServlet")
public class ControllerServlet extends HttpServlet {}
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到我的Eclipse项目,通过编辑web.xml如下

<servlet>
    <description>Servlet to print out Hello World!</description>
    <display-name>ControllerServlet</display-name>
    <servlet-name>ControllerServlet</servlet-name>
    <servlet-class>com.classmgt.servlet.ControllerServlet</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>ControllerServlet</servlet-name>
    <url-pattern>/ControllerServlet</url-pattern>
</servlet-mapping>
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但是,我得到以下异常:

SEVERE: A child container failed during start
java.util.concurrent.ExecutionException: org.apache.catalina.LifecycleException: Failed to start component [StandardEngine[Catalina].StandardHost[localhost].StandardContext[/ClassManagementSystem]]
    at java.util.concurrent.FutureTask$Sync.innerGet(Unknown Source)
    at java.util.concurrent.FutureTask.get(Unknown Source)
    at org.apache.catalina.core.ContainerBase.startInternal(ContainerBase.java:1123)
    at org.apache.catalina.core.StandardHost.startInternal(StandardHost.java:800)
    at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150)
    at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1559)
    at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1549)
    at java.util.concurrent.FutureTask$Sync.innerRun(Unknown Source)
    at java.util.concurrent.FutureTask.run(Unknown Source)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
    at java.lang.Thread.run(Unknown Source)
Caused by: org.apache.catalina.LifecycleException: Failed to start …
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eclipse mapping tomcat servlets illegalargumentexception

15
推荐指数
2
解决办法
3万
查看次数

使用Tomcat,@ WebFilter不能与web.xml中的<filter-mapping>一起使用

这是一个有效的web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app 
    xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    version="3.0">

    <session-config>
        <session-timeout>30</session-timeout>
    </session-config>

     <filter>
        <filter-name>rememberMeCookieFilter</filter-name>
        <filter-class>be.example.fun.jsp.filters.RememberMeCookieFilter</filter-class>
    </filter>

    <filter>
        <filter-name>mustBeSignedInFilter</filter-name>
        <filter-class>be.example.fun.jsp.filters.MustBeSignedInFilter</filter-class>
    </filter>

    <filter-mapping>
        <filter-name>rememberMeCookieFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <filter-mapping>
        <filter-name>mustBeSignedInFilter</filter-name>
        <url-pattern>/private/*</url-pattern>
    </filter-mapping>
</web-app>
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当我删除<filter>元素并使用以下注释时:

@WebFilter(filterName="rememberMeCookieFilter")
public class RememberMeCookieFilter implements Filter

@WebFilter(filterName="mustBeSignedInFilter")
public class MustBeSignedInFilter implements Filter
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然后Tomcat 7.0.14给我以下错误:

java.lang.IllegalArgumentException: Filter mapping must specify either a <url-pattern> or a <servlet-name>
    at org.apache.catalina.core.StandardContext.validateFilterMap(StandardContext.java:2956)
    at org.apache.catalina.core.StandardContext.addFilterMap(StandardContext.java:2915)
    at org.apache.catalina.deploy.WebXml.configureContext(WebXml.java:1180)
    at org.apache.catalina.startup.ContextConfig.webConfig(ContextConfig.java:1270)
        ...
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我按照这个问题的答案,但这对我不起作用.

以下是我的Web应用程序的依赖项:

<dependencies>
        <!-- SLF4J (+ LOGBack) for logging -->
        <dependency> …
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java tomcat java-ee servlet-filters

8
推荐指数
1
解决办法
9180
查看次数