我正在记录用户观看一系列视频的次数.现在,我正在尝试制作每天观看任何视频的用户数量的图表.
UserVideoWatching.where("created_at >= ? AND user_id != ?",1.month.ago, User.elephant.id).group("DATE(created_at)").reorder('created_at').count
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生成sql
SELECT COUNT(*) AS count_all, DATE(created_at) AS date_created_at FROM `user_video_watchings` WHERE (created_at >= '2013-01-27 10:43:24' AND user_id != 7) GROUP BY DATE(created_at) ORDER BY created_at
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这会为每天观看的所有视频产生正确的结果,但正如我所说,我只想向每位用户展示一次.
我想要的sql是
SELECT COUNT(DISTINCT user_id) AS count_all, DATE(created_at) AS date_created FROM `user_video_watchings` WHERE (created_at >= '2013-01-27 10:33:18' AND user_id != 7) GROUP BY DATE(created_at) ORDER BY created_at
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所以我认为
UserVideoWatching.where("created_at >= ? AND user_id != ?",1.month.ago, User.elephant.id).group("DATE(created_at)").reorder('created_at').select('COUNT(DISTINCT user_id) AS count_all, DATE(created_at) AS date_created')
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会做我想做的事.但这给了
[#<UserVideoWatching >, #<UserVideoWatching …Run Code Online (Sandbox Code Playgroud)