相关疑难解决方法(0)

我试图检测我的精灵节点是否被触摸,我不知道从哪里开始.

let Pineapple = SKSpriteNode(imageNamed: "Pineappleimg")
Pineapple.userInteractionEnabled = true
Pineapple.position = CGPoint(x: CGRectGetMidX(self.frame) - 200, y: CGRectGetMidY(self.frame));
self.addChild(Pineapple)

我正在为我正在构建的精灵工具包应用程序创建主菜单.在整个项目中,我使用SKScenes来保持我的关卡和实际的游戏玩法.但是,现在我需要一个主菜单,其中包含"Play","Levels","Shop"等按钮......但是,我现在添加按钮的方式感觉不太舒服,就像这样:

let currentButton = SKSpriteNode(imageNamed: button)  // Create the SKSpriteNode that holds the button

self.addChild(currentButton) // Add that SKSpriteNode to the SKScene

我检查按钮的触摸如下:

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    let touch = touches.first
    let touchLocation = touch!.location(in: self)

    for node in self.nodes(at: touchLocation) {
        guard let nodeName = node.name else {
            continue
        }
        if nodeName == ButtonLabel.Play.rawValue {
            DispatchQueue.main.asyncAfter(deadline: .now()) {
                let transition = SKTransition.reveal(with: .left, duration: 1)
                self.view?.presentScene(self.initialLevel, transition: transition)
                self.initialLevel.loadStartingLevel()
            }
            return
        }
        if nodeName …

我在这个精灵中有一个菜单按钮（skSpriteNode）和一个小的播放图标

mainButton.addChild (playIcon)
mainButton.name = "xyz"
addchild (mainButton)

好的，我给按钮起了个名字来检查是否触摸了这个名字的精灵。

当我触摸按钮内的图标子项时，touchedNode.name 为零。我为图标子项设置 isUserInteractionEnabled = false 。我想将触摸传递给父母。我怎样才能做到这一点。

  for touch in touches {

            let location = touch.location(in: self)
            let touchedNode  = self.atPoint(location)

            if (touchedNode.name != nil) {
                print ("node \(touchedNode.name!)")
            } else {
                continue
            }
 }