我的功能是:
CREATE OR REPLACE FUNCTION FnUpdateSalegtab09
(
iacyrid Integer,iRepId Integer,iDrId Integer,ivrid Integer,imode smallint,itrno
varchar,itrdate timestamp,iacid Integer,ivrno varchar,iSuppId Integer,icustname
varchar,inetamt money,idisrate real,idisamt money,iRoundOff real,ijrmid integer,iuserid
integer,iuserdtm timestamp,iVSNo integer,iRecdAmt money,icstrate real,icstsaleamt
money,icstamt money,itdrate real,itdamt money,icdrate real,icdamt money,iCessRate
real,iCessAmt money,iodesc1 varchar,ioamt1 money,iCashCredit boolean,iOrderNo
varchar,iOrderDate timestamp,iCustAdd2 varchar,iRemarks varchar,iWhoRetSl boolean,iPatName
varchar,iDrName varchar,iFormId integer,iSalesMan varchar,iCFMode smallint,iPatId
integer,iStkPtId integer,iDisType smallint,iBranchID integer
)
RETURNS void AS
'BEGIN
INSERT INTO gtab09
(
acyrid, RepId, DrId, vrid, mode, trno, trdate, acid, vrno, SuppId, custname, netamt,
disrate, disamt, RoundOff, jrmid, userid, …=# select row(0, 1) ;
row
-------
(0,1)
(1 row)
如何进入0同一个查询？我认为以下类型的工作,但有任何简单的方法吗？
=# select json_agg(row(0, 1))->0->'f1' ;
?column?
----------
0
(1 row)
没有运气类似阵列的语法[0].
谢谢!