我有一个关于在另一个JSON-LD schema.org标记中引用JSON-LD schema.org标记的问题.我有一个主要事件的页面位于,http://event.com/这里是JSON-LD标记.
<script type="application/ld+json">
{
"@context": "http://schema.org",
"@type": "Event",
"name": "MainEvent",
"startDate": "2016-04-21T12:00",
"location": {
...
}
}
</script>
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主事件有多个子事件,例如http://event.com/sub-event-1/,这里是JSON-LD标记:
<script type="application/ld+json">
{
"@context": "http://schema.org",
"@type": "Event",
"name": "SubEvent",
"startDate": "2016-04-21T12:00",
"location": {
...
}
}
</script>
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我要做的是将子事件标记为主事件的一部分.是否可以创建从主事件到子事件的引用?像这样的东西:
<script type="application/ld+json">
{
"@context": "http://schema.org",
"@type": "Event",
"name": "SubEvent",
"startDate": "2016-04-21T12:00",
"location": {
...
}
superEvent {
"url": "http://event.com/"
}
}
</script>
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如果可能,什么是正确的标记供参考.我找不到任何有关它的信息.
或者是否需要在每个SubEvent中嵌入MainEvent,如下所示:
<script type="application/ld+json">
{
"@context": "http://schema.org",
"@type": "Event",
"name": "SubEvent",
"startDate": "2016-04-21T12:00",
"location": { …Run Code Online (Sandbox Code Playgroud) 下面的微数据标记效果很好,谷歌的结构化数据测试工具显示了一个CollectionPage和WebSite/WebPage作为孩子。
<body itemscope itemtype="https://schema.org/CollectionPage">
<span itemscope itemtype="https://schema.org/WebSite" itemprop="hasPart">
<a href="https://springfield-xxxx.us" itemprop="url">Official site of Springfield</a>
</span>
<span itemscope itemtype="https://schema.org/WebPage" itemprop="hasPart">
<a href="https://facebook.com/group/XXXX" itemprop="url">Local events in Springfield</a>
</span>
<span itemscope itemtype="https://schema.org/WebPage" itemprop="hasPart">
<a href="https://news.us/city/springfield-xxxx" itemprop="url">Latest news in Springfield</a>
</span>
</body>
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但是,当我添加 JSON-LD 时,Google 的结构化数据测试工具会分别显示对象CollectionPage,WebPage/WebSite就像它们没有连接一样。这是一个带有 JSON-LD 的示例:
<!DOCTYPE html>
<html>
<head>
<script type="application/ld+json">
{
"description": "...",
"author": {"@type":"Person", "name": "Homer J. Simpson"},
"@type": "CollectionPage",
"url": "http://my-springfield.us/sites",
"publisher": {
"@type": "Organization",
"logo": …Run Code Online (Sandbox Code Playgroud)