似乎每次迭代对象时KFold都会生成相同的值,而Shuffle Split每次都会生成不同的索引.它是否正确？如果是这样,一个用户有什么用途？
cv = cross_validation.KFold(10, n_folds=2,shuffle=True,random_state=None)
cv2 = cross_validation.ShuffleSplit(10,n_iter=2,test_size=0.5)
print(list(iter(cv)))
print(list(iter(cv)))
print(list(iter(cv2)))
print(list(iter(cv2)))
产生以下输出:
[(array([1, 3, 5, 8, 9]), array([0, 2, 4, 6, 7])), (array([0, 2, 4, 6, 7]), array([1, 3, 5, 8, 9]))]
[(array([1, 3, 5, 8, 9]), array([0, 2, 4, 6, 7])), (array([0, 2, 4, 6, 7]), array([1, 3, 5, 8, 9]))]
[(array([4, 6, 3, 2, 7]), array([8, 1, 9, 0, 5])), (array([3, 6, 7, 0, 5]), array([9, 1, 8, 4, 2]))]
[(array([3, 0, 2, 1, 7]), array([5, …