相关疑难解决方法(0)

我试图做出HttpPost与multiPart/form-data通过我的Android应用程序.我有一个邮递员测试,正在使用我的api和postman中的请求预览,看起来像这样:

POST /api/0.1/content/upload HTTP/1.1
Host: 54.221.194.167
X-AUTHORIZATION: 166e649911ff424eb14446cf398bd7d6
Cache-Control: no-cache
Postman-Token: 2412eba9-f72d-6f3b-b124-6070b5b26644

----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="file01"

{"mime_type":"image/jpeg","title":"IMG_20140131_111622"}
----WebKitFormBoundaryE19zNvXGzXaLvS5C
Content-Disposition: form-data; name="file01"; filename="addedaslib.jpg"
Content-Type: image/jpeg


----WebKitFormBoundaryE19zNvXGzXaLvS5C

我试图使用我的android HttpPost使用multipart/form-data复制它,但它似乎没有工作.有没有办法"预览"我的请求,看看它实际上是如何发布到api？我究竟做错了什么？我的代码:

public HttpResponse invokeXAUTHPOSTService(String url, String token, File file) {


        client = new DefaultHttpClient();
        HttpPost request = new HttpPost(url);
        HttpResponse response = null; 
        MultipartEntity mpe = new MultipartEntity();
    try {


        Log.v("API", "URL:"+url);
        request.setHeader("Content-Type", "multipart/form-data");
        request.addHeader("X-AUTHORIZATION",token);
        request.addHeader("Cache-Control", "no-cache");

        DRPContentForUpload content = new DRPContentForUpload(file);
        String jsonObject = DRPJSONConverter.toJson(content);

        FormBodyPart part1= new FormBodyPart("file01", …