相关疑难解决方法(0)

找不到从方法glt.a引用的类com.google.android.gms.location.internal.ParcelableGeofence

我有一个主页是地图的应用程序.

不知道为什么我收到此错误并伴随此错误 Could not find class 'gpr', referenced from method gps.a

我已经更新了eclipse,所以我尝试使用新的SHA1指纹更改为API密钥.但这不起作用.

我的应用是在您打开应用时显示当前位置.它只是落入整个地图但在LOG猫我得到这些错误.这是我的Logcat

`07-08 12:54:39.897: I/Google Maps Android API(25749): Google Play services client version: 5077000

 07-08 12:54:39.907: I/dalvikvm(25749): Could not find method guj.a, referenced from method gqi.a

 07-08 12:54:39.907: W/dalvikvm(25749): VFY: unable to resolve static method 24936: Lguj;.a (Landroid/content/Context;)Lgri;

 07-08 12:54:39.907: D/dalvikvm(25749): VFY: replacing opcode 0x71 at 0x0003

 07-08 12:54:39.917: E/dalvikvm(25749): Could not find class 'gpr', referenced from method gps.a

 07-08 12:54:39.917: W/dalvikvm(25749): VFY: unable to resolve new-instance 4090 (Lgpr;) …
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gps android google-maps google-maps-api-2 google-maps-android-api-2

5
推荐指数
1
解决办法
9761
查看次数

Android:NoSuchMethodError:没有静态方法zzy(Ljava/lang/Object;

我创建了一个应用程序,我可以在其中访问两个波:FirebaseUI Auth和Firebase SDK身份验证(我知道这是非常错误的,我只在某些测试中使用它).好吧,从我添加谷歌访问权限,我无法访问SDK身份验证,应用程序总是崩溃,我不知道为什么.这是我的代码:

public class MainActivity extends AppCompatActivity
{
DialogProgress dialogProgress;
EditText editEmail;
EditText editPassword;
String email;
String password;
FirebaseAuth firebaseAuth;
final int REQUEST_CODE_GOOGLE = 100;
static Activity activity;

@Override
protected void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    activity = this;
    editEmail = (EditText) findViewById(R.id.editEmailA);
    editPassword = (EditText) findViewById(R.id.editPasswordA);
    firebaseAuth = FirebaseAuth.getInstance();

    if(firebaseAuth.getCurrentUser()!=null)
    {
        Toast.makeText(getApplicationContext(), "Bentornato " + firebaseAuth.getCurrentUser().getEmail().toString(), Toast.LENGTH_SHORT).show();
        Intent intent = new Intent(MainActivity.this,ProfileActivity.class);
        startActivity(intent);
        finish();
    }

    findViewById(R.id.accediButton).setOnClickListener(new View.OnClickListener()
    {
        @Override
        public void onClick(View v)
        {
            email = editEmail.getText().toString();
            password …
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java android firebase firebaseui

3
推荐指数
2
解决办法
7986
查看次数