model = sklearn.model_selection.GridSearchCV(
estimator = est,
param_grid = param_grid,
scoring = 'precision',
verbose = 1,
n_jobs = 1,
iid = True,
cv = 3)
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在 中sklearn.metrics.precision_score(y, y_pred,pos_label=[0]),我可以指定正标签,如何在 GridSearchCV 中也指定它?
如果无法指定,使用自定义评分时,如何定义?
我试过这个:
custom_score = make_scorer(precision_score(y, y_pred,pos_label=[0]),
greater_is_better=True)
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但我有错误:
NameError: name 'y_pred' is not defined
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