相关疑难解决方法(0)

我是一个相对较新的快速用户,现在,我需要利用iPhone的接近传感器.我跟距离无关,但我想知道iPhone附近有什么东西.

所以我在Objective-C中找到了这个代码,但是我在Swift中需要它.我尝试了一些方法,但任何方法都有效.所以这是我需要的代码:

- (void) activateProximitySensor {
    UIDevice *device = [UIDevice currentDevice];
    device.proximityMonitoringEnabled = YES;
    if (device.proximityMonitoringEnabled == YES) {
        [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(proximityChanged:) name:@"UIDeviceProximityStateDidChangeNotification" object:device];
    }
}

- (void) proximityChanged:(NSNotification *)notification {
    UIDevice *device = [notification object];
    NSLog(@"Detectat");

    //DO WHATEVER I WANT
}

编辑1:我试过的是这样的:

override func viewDidLoad() {
        super.viewDidLoad()
        UIDevice.currentDevice().proximityMonitoringEnabled = true;

        NSNotificationCenter.defaultCenter().addObserver(self, selector: Selector(proximityStateDidChange()), name:UIDeviceProximityStateDidChangeNotification, object: nil);
}

和功能:

func proximityStateDidChange() {
        //DO WHATEVER I WANT
}

我在执行应用程序时始终执行的功能.

编辑2:尝试Eric D.评论的代码

let sensor = MySensor() //declared in the …