相关疑难解决方法(0)

使用套接字,我不知道如何设置超时？

谢谢

int sock, connected, bytes_recieved;
char send_data [128] , recv_data[128];       
SOCKADDR_IN server_addr,client_addr;    
int sin_size;
int j = 0;

::socket(AF_INET, SOCK_STREAM, 0);

server_addr.sin_family = AF_INET;         
server_addr.sin_port = htons(4000);     
server_addr.sin_addr.s_addr = INADDR_ANY; 

::bind(sock, (struct sockaddr *)&server_addr, sizeof(struct sockaddr));
::listen(sock, 5);
::fflush(stdout);

while(1)
{  
    sin_size = sizeof(struct sockaddr_in);
    connected = ::accept(sock, (struct sockaddr *)&client_addr, &sin_size);

    while (1)
    {
        j++;

        ::send(connected, send_data, strlen(send_data), 0);  

        //dealing with lost communication ? 
        //and reastablishing communication
        //set timeout and reset on timeout error    
    }
}
::closesocket(sock);

是否存在超时交叉平台soulution以接受客户端使用accept功能而无需将套接字设置为非阻塞？

我知道我应该使用select它的功能,但我做错了什么？

SOCKET NativesAcceptClient(SOCKET s, int timeout)
{
   int iResult;
   struct timeval tv;
   fd_set rfds;
   FD_ZERO(&rfds);
   FD_SET(s, &rfds);

   tv.tv_sec = (long)timeout;
   tv.tv_usec = 0;

   iResult = select(s, &rfds, (fd_set *) 0, (fd_set *) 0, &tv);
   if(iResult > 0)
   {
      return accept(s, NULL, NULL);
   }
   else
   {
     //always here, even if i connect from another application
   }
   return 0;
}

如何解决？谢谢!