随着Mac OS X(Mavericks)上的第一个Java 8(b132)发布,使用新的java.time包的代码可以工作:
String input = "20111203123456";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern( "yyyyMMddHHmmss");
LocalDateTime localDateTime = LocalDateTime.parse( input, formatter );
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渲染:
2011-12-03T12:34:56
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但是当我按照DateTimeFormatter类doc中的指定添加"SS"作为秒的小数(和"55"作为输入)时,会抛出异常:
java.time.format.DateTimeParseException: Text '2011120312345655' could not be parsed at index 0
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该文档说默认使用严格模式,并且需要与输入数字相同数量的格式字符.所以我很困惑为什么这段代码失败了:
String input = "2011120312345655";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern( "yyyyMMddHHmmssSS");
LocalDateTime localDateTime = LocalDateTime.parse( input, formatter );
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使用文档中的示例("978")的另一个示例(失败):
String input = "20111203123456978";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern( "yyyyMMddHHmmssSSS");
LocalDateTime localDateTime = LocalDateTime.parse( input, formatter );
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这个例子工作,添加一个小数点(但我发现在doc中没有这样的要求):
String input = "20111203123456.978";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern( …Run Code Online (Sandbox Code Playgroud) 我想从以下模式解析LocalDateTime:
yyyyMMddHHmmss000000
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这意味着通常的"yyyy ... ss"然后是六个尾随的零.
因此,格式化工作正常:
String p = "yyyyMMddHHmmss'000000'";
LocalDateTime.now().format(DateTimeFormatter.ofPattern(p));
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然后解析:
String p, v;
p = "yyyyMMddHHmmss"; // without '000000'
v = "20160131235930";
LocalDateTime.parse(v, DateTimeFormatter.ofPattern(p)); // it works
p = "yyyy-MMddHHmmss'000000'"; // with '-' in between
v = "2016-0131235930000000";
LocalDateTime.parse(v, DateTimeFormatter.ofPattern(p)); // it works
p = "yyyyMMddHHmmss'000000'"; // with '000000' but without '-'
v = "20160131235930000000";
LocalDateTime.parse(v, DateTimeFormatter.ofPattern(p)); // it throws Exception
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例外情况:
java.time.format.DateTimeParseException: Text '20160131235930000000' could not be parsed at index 0
at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1947)
at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1849)
at java.time.LocalDateTime.parse(LocalDateTime.java:492) …Run Code Online (Sandbox Code Playgroud)