这个问题已在C++上下文中提出,但我对Java很好奇.关于虚拟方法的担忧不适用(我认为),但如果您遇到这种情况:
abstract class Pet
{
private String name;
public Pet setName(String name) { this.name = name; return this; }
}
class Cat extends Pet
{
public Cat catchMice() {
System.out.println("I caught a mouse!");
return this;
}
}
class Dog extends Pet
{
public Dog catchFrisbee() {
System.out.println("I caught a frisbee!");
return this;
}
}
class Bird extends Pet
{
public Bird layEgg() {
...
return this;
}
}
{
Cat c = new Cat();
c.setName("Morris").catchMice(); // error! setName returns …Run Code Online (Sandbox Code Playgroud)