相关疑难解决方法(0)

我正在解析一些命令行参数,并且大多数都需要传递给一个方法,但不是全部.

parser = argparse.ArgumentParser()
parser.add_argument("-d", "--dir", help = "Directory name", type = str, default = "backups")
parser.add_argument("-n", "--dbname", help = "Name of the database", type = str, default = "dmitrii")
parser.add_argument("-p", "--password", help = "Database password", type = str, default = "1123581321")
parser.add_argument("-u", "--user", help = "Database username", type = str, default = "Dmitriy")
parser.add_argument("-a", "--archive", help = "Archive backup", action="store_true")
args = parser.parse_args()

backup(**vars(args)) # the method where i need to pass most of the arguments, except archive. Now …

我有一个Python脚本,它运行两个接受相同选项的子命令--config.我想创建一个第三个子命令,可以按顺序一起运行前两个子命令.

使用argparse,我为每个子命令创建了一个subparser,以及第三个subparser,其父项是两个子命令.只是为了澄清:

subcommand1 = subparsers.add_parser('subcommand1')
subcommand1.add_argument('--config', help="The config")

subcommand2 = subparsers.add_parser('subcommand2')
subcommand2.add_argument('--config', help="The config")

wrappercommand = subparsers.add_parser('wrappercommand', 
                                       parents=[subcommand1, subcommand2], 
                                       conflict_handler='resolve')

当我运行wrappercommand或subcommand2时,一切正常.但是,subcommand1中断,以此为输出:

$ run_command.py subcommand1 --config path_to_config.ini

usage: run_command.py subcommand1 config 

optional arguments:
  help                  show this help message and exit
  config                The config

看起来argparse已将关键字arg(" - config")转换为位置关键字("config").这是argparse解决冲突选项时的预期行为吗？