相关疑难解决方法(0)

我有一个when想要匹配两件事的构造：

when (activeRequest.verb to activeRequest.resourceType) {
    GET to "all" -> allGet()
    PUT to "foo" -> fooPut()
    GET to "foo" -> fooGet()
    POST to "bar" -> barPost()
    GET to "bar" -> barGet()
    COPY to "bar" -> barCopy()
    DELETE to "bar" -> barDelete()
    else -> logMismatch()
}

使用to对构造函数是执行此操作的唯一方法吗？Pair 的使用似乎很奇怪（尽管它有效）。我很难找到它，因为代码片段像

for ((key, value) in hashMap) {
    println("$key $value)
}

让我觉得我应该能够在when代码中做类似的事情，例如

when (activeRequest.verb, activeRequest.resourceType) {
    (GET, "all") -> allGet()
    (PUT, "foo") -> fooPut()
   ...
    else -> logMismatch()
} …