相关疑难解决方法(0)

在Java中,这些之间有什么区别:

Object o1 = ....
o1.getClass().getSimpleName();
o1.getClass().getName();
o1.getClass().getCanonicalName();

我多次检查过Javadoc,但这从未解释过.我也进行了测试,并没有反映这些方法被调用的方式背后的任何真正含义.

当我编译时,我得到了上述错误.我的gradle文件如下: -

apply plugin: 'com.android.application'
apply plugin: 'kotlin-android'
apply plugin: 'kotlin-android-extensions'

android {
    compileSdkVersion 23
    buildToolsVersion "24.0.0 rc2"

    defaultConfig {
        applicationId "package.name"
        minSdkVersion 16
        targetSdkVersion 23
        versionCode 6
        versionName "2.0"
    }

    buildTypes {
        debug {
            minifyEnabled false
            signingConfig signingConfigs.debug
        }
        release {
            minifyEnabled true
            proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
            signingConfig signingConfigs.release
        }
    }
    sourceSets {
        main.java.srcDirs += 'src/main/kotlin'
    }
}

dependencies {
    compile fileTree(dir: 'libs', include: ['*.jar'])
    testCompile 'junit:junit:4.12'
    compile "com.android.support:appcompat-v7:$support_version"
    compile "org.jetbrains.kotlin:kotlin-stdlib:$kotlin_version"
    compile "org.jetbrains.anko:anko-sdk15:$anko_version"
    compile "org.jetbrains.anko:anko-support-v4:$anko_version"
    compile "com.android.support:recyclerview-v7:$support_version"
}

buildscript { …