相关疑难解决方法(0)

我正在group by通过Sequelize 寻找查询,似乎无法找到任何文档.

SELECT column, count(column)  
FROM table 
GROUP BY column

我有一个给定的数据库,其中包含冗长,繁琐的列名.有没有办法将表名映射到模型中更短和更具描述性的propertyNames？就像是

var Employee = sql.define('Employee', {
    id : {type : Sequelize.INTEGER , primaryKey: true, map : "veryLongNameForJustTheId"}
},{
     tableName: 'cumbersomeTableName',
     timestamps: false
});;

我在节点js中使用sequelize ORM。我加入两个表并得到结果，但结果以表名作为前缀返回。

var Sequelize = require('sequelize');
var sequelize = new Sequelize('test', 'root', '', {
    // configuration
  }
});

const db = {};

db.Sequelize = Sequelize;  
db.sequelize = sequelize;

db.role = require('./../model/definitions/role')(sequelize, Sequelize);  
db.admin = require('./../model/definitions/admin')(sequelize, Sequelize);  

  db.admin.findAll({ 
    include: [{ 
      model: db.role,                      
      where:{status : 'Active'},     
    }],
    raw: true      

  }).then(function(result) {
      console.log(result);
  }).catch(function(error) {
    console.log(error);
  }).done();

现在我得到这个结果：

[{
    "id": 36,                
    "email": "test@gmail.com",
    "username": "test",
    "status": "Active",
    "role.role_id": 1,
    "role.role_name": "Admin"
}]

但我需要这个结果：

[{
    "id": 36,                
    "email": "test@gmail.com",
    "username": "test",
    "status": "Active",
    "role_id": …

我正在尝试将此查询转换为序列化查询对象，正确的方法是什么？

SELECT families.id, count('answers.familyId') FROM families LEFT JOIN 
answers on families.id = answers.familyId WHERE answers.isActive=1 AND
answers.answer=1 GROUP BY families.id HAVING COUNT('answers.familyId')>=6