相关疑难解决方法(0)

我有一个包含视频的NSURL,我想每秒十次录制该视频的一帧.我有代码可以捕获我的播放器的图像,但是我无法将其设置为每秒捕获10帧.我正在尝试这样的事情,但是它返回了视频的相同初始帧,正确的次数？这是我有的:

AVAsset *asset = [AVAsset assetWithURL:videoUrl];
CMTime vidLength = asset.duration;
float seconds = CMTimeGetSeconds(vidLength);
int frameCount = 0;
for (float i = 0; i < seconds;) {
    AVAssetImageGenerator *imageGenerator = [[AVAssetImageGenerator alloc]initWithAsset:asset];
    CMTime time = CMTimeMake(i, 10);
    CGImageRef imageRef = [imageGenerator copyCGImageAtTime:time actualTime:NULL error:NULL];
    UIImage *thumbnail = [UIImage imageWithCGImage:imageRef];
                                CGImageRelease(imageRef);
NSString* filename = [NSString stringWithFormat:@"Documents/frame_%d.png", frameCount];
NSString* pngPath = [NSHomeDirectory() stringByAppendingPathComponent:filename];

[UIImagePNGRepresentation(thumbnail) writeToFile: pngPath atomically: YES];
frameCount++;
i = i + 0.1;
}

但是,不是在视频的当前时间i获取帧,我只是得到初始帧？

如何每秒10次获取视频帧？

谢谢您的帮助 :)

我正在关注此代码以获取视频中的所有帧.在这个链接中,他试图在特定时间获得一个框架.但我需要得到所有帧.这是我的代码......

var mutableVideoURL = NSURL()
var videoFrames = [UIImage]()

let asset : AVAsset = AVAsset(url: self.mutableVideoURL as URL)
let mutableVideoDuration = CMTimeGetSeconds(asset.duration)
print("-----Mutable video duration = \(mutableVideoDuration)")
let mutableVideoDurationIntValue = Int(mutableVideoDuration)
print("-----Int value of mutable video duration = \(mutableVideoDurationIntValue)")

for index in 0..<mutableVideoDurationIntValue {
   self.generateFrames(url: self.mutableVideoURL, fromTime: Float64(index))
}

    func generateFrames(url : NSURL, fromTime:Float64) {
        let asset: AVAsset = AVAsset(url: url as URL)
        let assetImgGenerate : AVAssetImageGenerator = AVAssetImageGenerator(asset: asset)
        assetImgGenerate.appliesPreferredTrackTransform = true
        let time        : CMTime = …