我正在寻找NumPy计算两个numpy数组(x和y)之间的Mahalanobis距离的方法.以下代码可以使用Scipy的cdist函数正确计算相同的代码.由于此函数在我的情况下计算不必要的matix,我想要更直接的方式使用NumPy计算它.
import numpy as np
from scipy.spatial.distance import cdist
x = np.array([[[1,2,3,4,5],
[5,6,7,8,5],
[5,6,7,8,5]],
[[11,22,23,24,5],
[25,26,27,28,5],
[5,6,7,8,5]]])
i,j,k = x.shape
xx = x.reshape(i,j*k).T
y = np.array([[[31,32,33,34,5],
[35,36,37,38,5],
[5,6,7,8,5]],
[[41,42,43,44,5],
[45,46,47,48,5],
[5,6,7,8,5]]])
yy = y.reshape(i,j*k).T
results = cdist(xx,yy,'mahalanobis')
results = np.diag(results)
print results
[ 2.28765854 2.75165028 2.75165028 2.75165028 0. 2.75165028
2.75165028 2.75165028 2.75165028 0. 0. 0. 0.
0. 0. ]
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我的试用版:
VI = np.linalg.inv(np.cov(xx,yy))
print np.sqrt(np.dot(np.dot((xx-yy),VI),(xx-yy).T))
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任何人都可以纠正这种方法吗?
这是它的公式: