相关疑难解决方法(0)

我有一个AsyncTask应该检查网络访问主机名.但是doInBackground()永远不会超时.有人有线索吗？

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

我一直在研究一个Android项目,我想要一些API来获取信息.看起来这应该是非常基本的!

这是我的代码的一般要点:

private InputStream retrieveStream2(String url)
{
    DefaultHttpClient client = new DefaultHttpClient();

    HttpGet getRequest = new HttpGet(url);
    System.out.println("getRequest == " + getRequest);
    try {


        HttpResponse getResponse = client.execute(getRequest);//here is teh problem
        final int statusCode = getResponse.getStatusLine().getStatusCode();


        if (statusCode != HttpStatus.SC_OK)
        {
            Log.w(getClass().getSimpleName(),
                    "Error " + statusCode + " for URL " + url);
            return null;
        }

        HttpEntity getResponseEntity = getResponse.getEntity();
        return getResponseEntity.getContent();

    }
    catch (Exception e)
    {
        getRequest.abort();
        Log.w(getClass().getSimpleName(), "Error for URL, YO " + url, e);
    }
    return null; …