相关疑难解决方法(0)

我有以下数据:

{"action":"CREATE","docs":1,"date":"2016 Jun 26 12:00:12","userid":"1234"}
{"action":"REPLACE","docs":2,"date":"2016 Jun 27 12:00:12","userid":"1234"}
{"action":"REPLACE","docs":1,"date":"2016 Jun 27 13:00:12","userid":"1234"}
{"action":"CREATE","docs":1,"date":"2016 Jun 28 12:00:12","userid":"3431"}
{"action":"REPLACE","docs":2,"date":"2016 Jun 28 13:00:12","userid":"3431"}
{"action":"CREATE","docs":1,"date":"2016 Jun 29 12:00:12","userid":"9999"}

为了按日期(降序)获取每个唯一用户订单的记录,我使用了如下所示的Top Hits:

"aggs": {
  "user_bucket": {
    "terms": {
      "field": "userid"
    },
    "aggs": {
      "user_latest_count": {
        "top_hits": {
          "size": 1,
          "sort": [
            {
              "data": {
                "order": "desc"
              }
            }
          ],
          "_source": {
            "include": [
              "docs"
            ]
          }
        }
      }
    }
  }
}

以上查询的结果如下:

{"action":"REPLACE","docs":1,"date":"2016 Jun 27 13:00:12","userid":"1234"}
{"action":"REPLACE","docs":2,"date":"2016 Jun 28 13:00:12","userid":"3431"}
{"action":"CREATE","docs":1,"date":"2016 Jun 29 12:00:12","userid":"9999"}

现在,我想进一步聚合这个,结果如下: …