对于列表["foo", "bar", "baz"]和列表中的项目"bar",如何在Python中获取其索引(1)?
假设我有以下pandas数据帧:
df = DataFrame({'A' : [5,6,3,4], 'B' : [1,2,3, 5]})
df
A B
0 5 1
1 6 2
2 3 3
3 4 5
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我可以根据特定值进行子集化:
x = df[df['A'] == 3]
x
A B
2 3 3
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但是我如何根据值列表进行子集化? - 这样的事情:
list_of_values = [3,6]
y = df[df['A'] in list_of_values]
Run Code Online (Sandbox Code Playgroud) 我有一个Python pandas DataFrame rpt:
rpt
<class 'pandas.core.frame.DataFrame'>
MultiIndex: 47518 entries, ('000002', '20120331') to ('603366', '20091231')
Data columns:
STK_ID 47518 non-null values
STK_Name 47518 non-null values
RPT_Date 47518 non-null values
sales 47518 non-null values
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我可以过滤库存ID '600809'如下的行:rpt[rpt['STK_ID'] == '600809']
<class 'pandas.core.frame.DataFrame'>
MultiIndex: 25 entries, ('600809', '20120331') to ('600809', '20060331')
Data columns:
STK_ID 25 non-null values
STK_Name 25 non-null values
RPT_Date 25 non-null values
sales 25 non-null values
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我想把一些股票的所有行放在一起,例如['600809','600141','600329'].这意味着我想要这样的语法:
stk_list = ['600809','600141','600329']
rst = rpt[rpt['STK_ID'] in stk_list] # …Run Code Online (Sandbox Code Playgroud)