相关疑难解决方法(0)

@cases => [{"name"=>"25 Cases per 60 day", "count"=>0},
 {"name"=>"30 Cases for 60 days", "count"=>8},
 {"name"=>"10 Cases per 60 days", "count"=>5}]

如果我有一个包含先前结果的对象,我该如何按countDESC顺序排序？要获取实例变量,cases我做了

ClassName.all.collect{|e| {'name' => e.name, 'count' => e.contracts.count}}

我的输入哈希:

h = [
  {user_id: 1, bookings_nd: 3}, 
  {user_id: 2, bookings_nd: 10}, 
  {user_id: 3, bookings_nd: 2}
]

我需要:

h = [
  {user_id: 2, bookings_nd: 10}, 
  {user_id: 1, bookings_nd: 3},
  {user_id: 3, bookings_nd: 2}
]

怎么做？