相关疑难解决方法(0)

所以我在WAMP环境中使用php 5.2.6.

我正在尝试使用json_decode函数将json字符串转换为数组.JSON来自其他地方的REST API,因此我无法控制JSON字符串的格式.这是我正在尝试使用的json字符串之一的示例:

[{
    "webinarKey":795855906,
    "sessionKey":100000000041808257,
    "startTime":"2011-12-16T13:56:15Z",
    "endTime":"2011-12-16T14:48:37Z",
    "registrantsAttended":2
}]

我特意在这里找到sessionKey值.PHP将值视为一个浮点数,我似乎无法做任何事情来检索原始值.

我尝试过以下方法:

json_decode($json, true, 512, JSON_BIGINT_AS_STRING);
# This produces the following error because my php version isn't up to snuff and I
# can't upgrade to the version required
# Warning: json_decode() expects at most 2 parameters, 4 given

我也试过这个:

$json_obj = json_decode($json, true);
number_format($json_obj[0]["sessionKey"], 0, '.', '');
# This results in precision issues where the value was 100000000041808257
# but is number_formated out as 100000000041808256

正如我所说,升级到php 5.4(支持4参数json_decode调用)不是一个选项.请帮忙!

谢谢!