我在这段代码的输出中得到了很多小数(华氏温度到摄氏温度转换器).
我的代码目前看起来像这样:
def main():
printC(formeln(typeHere()))
def typeHere():
global Fahrenheit
try:
Fahrenheit = int(raw_input("Hi! Enter Fahrenheit value, and get it in Celsius!\n"))
except ValueError:
print "\nYour insertion was not a digit!"
print "We've put your Fahrenheit value to 50!"
Fahrenheit = 50
return Fahrenheit
def formeln(c):
Celsius = (Fahrenheit - 32.00) * 5.00/9.00
return Celsius
def printC(answer):
answer = str(answer)
print "\nYour Celsius value is " + answer + " C.\n"
main()
所以我的问题是,如何使程序围绕小数点后两位的每个答案？
我只是用Python测试工程中的数值方法的一个例子.
from numpy import zeros, array
from math import sin, log
from newtonRaphson2 import *
def f(x):
f = zeros(len(x))
f[0] = sin(x[0]) + x[1]**2 + log(x[2]) - 7.0
f[1] = 3.0*x[0] + 2.0**x[1] - x[2]**3 + 1.0
f[2] = x[0] + x[1] + x[2] -5.0
return f
x = array([1.0, 1.0, 1.0])
print newtonRaphson2(f,x)
当我运行它时,它显示以下错误:
File "example NR2method.py", line 8, in f
f[0] = sin(x[0]) + x[1]**2 + log(x[2]) - 7.0
ValueError: math domain error …我写了一个名为的函数analyze_the_shape,它接受一个2D顶点列表,使得列表按照2D欧几里德空间中顶点的顺时针遍历顺序排列.
我在解释器中调用它并给出[(0, 0), (0, 4.0), (4.0, 4.0), (4.0, 0)]输入但是我得到了ValueError : math domain error.我希望看到return ["SQUARE", 4.0].我能做什么 ？
import math
def analyze_the_shape(liste):
if len(liste) == 2 :
d = ( (liste[1][0] - liste[0][0])**2 + (liste[1][1] - liste[0][1])**2 )**(0.5)
return ["LINESEGMENT", d ]
if len(liste) == 4 :
d1 = abs(( (liste[1][0] - liste[0][0])**2 + (liste[1][1] - liste[0][1])**2 )**(0.5))
d2 = abs(( (liste[2][0] - liste[1][0])**2 + (liste[2][1] - liste[1][1])**2 )**(0.5))
d3 = abs(( (liste[3][0] - …是什么原因引起的问题？
from math import sqrt
print "a : "
a = float(raw_input())
print "b : "
b = float(raw_input())
print "c : "
c = float(raw_input())
d = (a + b + c)/2
s = sqrt(d*(d-a)*(d-b)*(d-c))
print "a+b+c =", a, b, c
print "Distr. =", d*2, "Area =", s
错误：
Traceback (most recent call last):
File "C:/Python27/fájlok/háromszög terület2.py", line 11, in <module>
s = sqrt(d*(d-a)*(d-b)*(d-c))
ValueError: math domain error