相关疑难解决方法(0)

我正在尝试构建我正在构建的Django站点的搜索,并且在搜索中我正在搜索3种不同的模型.为了获得搜索结果列表的分页,我想使用通用的object_list视图来显示结果.但要做到这一点,我必须将3个查询集合并为一个.

我怎样才能做到这一点？我试过这个:

result_list = []            
page_list = Page.objects.filter(
    Q(title__icontains=cleaned_search_term) | 
    Q(body__icontains=cleaned_search_term))
article_list = Article.objects.filter(
    Q(title__icontains=cleaned_search_term) | 
    Q(body__icontains=cleaned_search_term) | 
    Q(tags__icontains=cleaned_search_term))
post_list = Post.objects.filter(
    Q(title__icontains=cleaned_search_term) | 
    Q(body__icontains=cleaned_search_term) | 
    Q(tags__icontains=cleaned_search_term))

for x in page_list:
    result_list.append(x)
for x in article_list:
    result_list.append(x)
for x in post_list:
    result_list.append(x)

return object_list(
    request, 
    queryset=result_list, 
    template_object_name='result',
    paginate_by=10, 
    extra_context={
        'search_term': search_term},
    template_name="search/result_list.html")

但这不起作用当我尝试在通用视图中使用该列表时,我收到错误.该列表缺少clone属性.

有人知道如何合并三个列表page_list,article_list和post_list？