相关疑难解决方法(0)

正如标题所示,我想选择用a组成的每组行的第一行GROUP BY.

具体来说,如果我有一个purchases看起来像这样的表:

SELECT * FROM purchases;

我的输出:

id | customer | total
---+----------+------
 1 | Joe      | 5
 2 | Sally    | 3
 3 | Joe      | 2
 4 | Sally    | 1

我想查询每个产品id的最大购买量(total)customer.像这样的东西:

SELECT FIRST(id), customer, FIRST(total)
FROM  purchases
GROUP BY customer
ORDER BY total DESC;

预期产出:

FIRST(id) | customer | FIRST(total)
----------+----------+-------------
        1 | Joe      | 5
        2 | Sally    | 3

我有3张桌子:

users(id, account_balance)
grocery(user_id, date, amount_paid)
fishmarket(user_id, date, amount_paid)

对于具有不同日期和金额的相同user_id,两个fishmarket和grocery表可能有多次出现,或者对于任何给定用户都没有任何内容.当我尝试以下查询时:

SELECT
     t1."id" AS "User ID",
     t1.account_balance AS "Account Balance",
     count(t2.user_id) AS "# of grocery visits",
     count(t3.user_id) AS "# of fishmarket visits"
FROM users t1
LEFT OUTER JOIN grocery t2 ON (t2.user_id=t1."id") 
LEFT OUTER JOIN fishmarket t3 ON (t3.user_id=t1."id") 
GROUP BY t1.account_balance,t1.id
ORDER BY t1.id

它会产生不正确的结果:"1", "12", "12".
但是,当我尝试LEFT JOIN只有一个表时,它会产生正确的结果,无论是访问grocery还是fishmarket访问"1", "3", "4".

我在这做错了什么？
我正在使用PostgreSQL 9.1.