考虑在大小为N-by-M的网格上排列的一组点.我正在尝试构建邻接矩阵,以便连接相邻点.
例如,在带有图形的3x3网格中:
1-2-3
| | |
4-5-6
| | |
7-8-9
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我们应该有相应的邻接矩阵:
+---+------------------------------------------------------+
| | 1 2 3 4 5 6 7 8 9 |
+---+------------------------------------------------------+
| 1 | 0 1 0 1 0 0 0 0 0 |
| 2 | 1 0 1 0 1 0 0 0 0 |
| 3 | 0 1 0 0 0 1 0 0 0 |
| 4 | 1 0 0 0 1 0 1 0 0 |
| 5 …Run Code Online (Sandbox Code Playgroud) 我现在一直在与这个问题作斗争,我知道这很简单 - 但我对Python或NetworkX没什么经验.我的问题非常简单,我试图绘制一个大型数据集(大约200行/列)的矩阵,看起来像这样.第一行和第一列是相同的.
A,B,C,D,E,F,G,H,I,J,K
A,0,1,1,0,1,1,1,1,0,1,0
B,1,0,0,0,1,1,1,1,0,1,0
C,1,0,0,0,1,1,1,1,0,1,0
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它只是一个显示人们如何连接的矩阵,我想要的只是导入和绘制这个csv文件,并在NetworkX中使用它的相应标签.
我有这个文件(people.csv),并在这里查看以前的答案,似乎最好的方法是将数据放在一个numpy数组中.
这似乎有一个问题:
import numpy as np
import networkx as nx
import matplotlib.pyplot as plt
from numpy import genfromtxt
import numpy as np
mydata = genfromtxt('mouse.csv', delimiter=',')
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我得到以下输出:
File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/numpy/lib/npyio.py", line 1272, in genfromtxt
fhd = iter(np.lib._datasource.open(fname, 'rbU'))
File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/numpy/lib/_datasource.py", line 145, in open
return ds.open(path, mode)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/numpy/lib/_datasource.py", line 472, in open
found = self._findfile(path)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/numpy/lib/_datasource.py", line 323, in _findfile
if self.exists(name):
File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/numpy/lib/_datasource.py", line 417, …Run Code Online (Sandbox Code Playgroud)