我正在尝试生成这样的XML:
<?xml version="1.0"?>
<!DOCTYPE APIRequest SYSTEM
"https://url">
<APIRequest>
<Head>
<Key>123</Key>
</Head>
<ObjectClass>
<Field>Value</Field
</ObjectClass>
</APIRequest>
我有一个用XMLSerialization属性装饰的类(ObjectClass),如下所示:
[XmlRoot("ObjectClass")]
public class ObjectClass
{
[XmlElement("Field")]
public string Field { get; set; }
}
而我真正的hacky直觉思想让我的工作就是在序列化时这样做:
ObjectClass inst = new ObjectClass();
XmlSerializer serializer = new XmlSerializer(inst.GetType(), "");
StringWriter w = new StringWriter();
w.WriteLine(@"<?xml version=""1.0""?>");
w.WriteLine("<!DOCTYPE APIRequest SYSTEM");
w.WriteLine(@"""https://url"">");
w.WriteLine("<APIRequest>");
w.WriteLine("<Head>");
w.WriteLine(@"<Field>Value</Field>");
w.WriteLine(@"</Head>");
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("", "");
serializer.Serialize(w, inst, ns);
w.WriteLine("</APIRequest>");
但是,这会生成如下XML:
<?xml version="1.0"?>
<!DOCTYPE APIRequest SYSTEM
"https://url">
<APIRequest>
<Head>
<Key>123</Key>
</Head>
<?xml …