相关疑难解决方法(0)

编辑:我添加了示例的源代码.

我遇到了这个例子:

char source[MAX] = "123456789";
char source1[MAX] = "123456789";
char destination[MAX] = "abcdefg";
char destination1[MAX] = "abcdefg";
char *return_string;
int index = 5;

/* This is how strcpy works */
printf("destination is originally = '%s'\n", destination);
return_string = strcpy(destination, source);
printf("after strcpy, dest becomes '%s'\n\n", destination);

/* This is how strncpy works */
printf( "destination1 is originally = '%s'\n", destination1 );
return_string = strncpy( destination1, source1, index );
printf( "After strncpy, destination1 becomes '%s'\n", destination1 );

哪个产生了这个输出: …

我想将一个字符串复制到一个char数组,而不是溢出缓冲区.

因此,如果我有一个大小为5的字符数组,那么我想将一个字符串中最多5个字节复制到其中.

这样做的代码是什么？