相关疑难解决方法(0)

我有一个foo发出Ajax请求的函数.我怎样才能从中回复foo？

我尝试从success回调中返回值,并将响应分配给函数内部的局部变量并返回该变量,但这些方法都没有实际返回响应.

function foo() {
    var result;

    $.ajax({
        url: '...',
        success: function(response) {
            result = response;
            // return response; // <- I tried that one as well
        }
    });

    return result;
}

var result = foo(); // It always ends up being `undefined`.

我想在ZingChart Feed中绘制2个系列数据.下面是我的脚本代码.

<script>
var chartData = {
    "type":"line",
    "refresh": {
        "type": "feed",
        "transport": "js",
        "url": "feed()",
        "interval": 1000
    },
    "series":[
        {
            "values":[]

        },
        {
            "values":[]
        }
    ]
};



window.onload = function() {
    zingchart.render({
        id: "chartDiv",
        data: chartData,
        height: 600,
        width: "100%"
    });
};

window.feed = function(callback) {
    $.ajax({
        type: "GET",
        dataType: "json",
        headers: {
            Accept: "application/json",
            "Access-Control-Allow-Origin": "*"
        },
        url: "/PerformanceMonitor/showProcessUsage/${processName}",
        success: function (data) {
            var mem = data.mem.size/100000;
            var tick = {
                plot0: parseInt(mem)
                                };
            callback(JSON.stringify(tick));
            var tick2 = …