相关疑难解决方法(0)

我不明白为什么在下面的代码中,当我实例化一个类型的对象时daughter,默认的grandmother()构造函数被调用？

我认为grandmother(int)应该调用构造函数(遵循我的mother类构造函数的规范),或者由于虚拟继承,这个代码根本不应该编译.

这里编译器grandmother在我的后面静默调用默认构造函数,而我从来没有要求它.

#include <iostream>

class grandmother {
public:
    grandmother() {
        std::cout << "grandmother (default)" << std::endl;
    }
    grandmother(int attr) {
        std::cout << "grandmother: " << attr << std::endl;
    }
};

class mother: virtual public grandmother {
public:
    mother(int attr) : grandmother(attr) {
        std::cout << "mother: " << attr << std::endl;
    }
};

class daughter: virtual public mother {
public:
    daughter(int attr) : mother(attr) {
        std::cout << "daughter: " << …