我设法用自定义约束实现表单验证,但现在我想用JSON数据做同样的事情.
如何将自定义验证规则应用于JSON解析器？
示例:客户端的POST请求包含用户名(username),我不仅要确保此参数是非空文本,还要确保此用户实际存在于数据库中.
// In the controller...
def postNew = Action { implicit request =>
request.body.asJson.map { json =>
json.validate[ExampleCaseClass] match {
case success: JsSuccess[ExampleCaseClass] =>
val obj: ExampleCaseClass = success.get
// ...do something with obj...
Ok("ok")
case error: JsError =>
BadRequest(JsError.toFlatJson(error))
}
} getOrElse(BadRequest(Json.obj("msg" -> "JSON request expected")))
}
// In ExampleCaseClass.scala...
case class ExampleCaseClass(username: String, somethingElse: String)
object ExampleCaseClass {
// That's what I would use for a form:
val userCheck: Mapping[String] = nonEmptyText.verifying(userExistsConstraint)
implicit val …我正在查询spotify api以获取给定查询的轨道列表ws,当我将JSON数据转换为案例类时,我收到的错误是我还没弄明白...
class SearchController @Inject() (
val ws: WSClient
) extends Controller {
case class TrackSearch(href: String)
implicit val trackResultsReads: Reads[TrackSearch] = (
(__ \ "tracks" \ "href").read[String]
)(TrackSearch.apply _)
def index = Action.async { implicit request =>
search("track", param(request, "q")).map { r =>
val ts = r.json.as[TrackSearch]
println(ts)
Ok
}
}
private def search(category: String, query: String): Future[Try[WSResponse]] = {
ws.url("https://api.spotify.com/v1/search")
.withQueryString("q" -> query, "type" -> category)
.get()
.map(Success(_))
.recover { case x => Failure(x) }
} …