相关疑难解决方法(0)

我想编写一个将CamelCase转换为人类可读名称的方法.

这是测试用例:

public void testSplitCamelCase() {
    assertEquals("lowercase", splitCamelCase("lowercase"));
    assertEquals("Class", splitCamelCase("Class"));
    assertEquals("My Class", splitCamelCase("MyClass"));
    assertEquals("HTML", splitCamelCase("HTML"));
    assertEquals("PDF Loader", splitCamelCase("PDFLoader"));
    assertEquals("A String", splitCamelCase("AString"));
    assertEquals("Simple XML Parser", splitCamelCase("SimpleXMLParser"));
    assertEquals("GL 11 Version", splitCamelCase("GL11Version"));
}

我有一个只有一个组的正则表达式模式.我需要在模式后面的输入字符串中查找文本并仅替换匹配组1.例如,我有正则表达式模式和要应用的字符串,如下所示.替换字符串是"<---->"

Pattern p = Pattern.compile("\\w*(lan)\\w+");
Matcher m = p.matcher("plan plans lander planitia");

预期的结果是

plan p<--->s <--->der p<--->itia

我尝试了以下方法

    String test = "plan plans lander planitia";
    Pattern p = Pattern.compile("\\w*(lan)\\w+");
    Matcher m = p.matcher(test);
    String result = "";
    while(m.find()){
        result = test.replaceAll(m.group(1),"<--->");
    }
    System.out.print(result);

这给出了结果

p<---> p<--->s <--->der p<--->itia

另一种方法

    String test = "plan plans lander planitia";
    Pattern p = Pattern.compile("\\w*(lan)\\w+");
    Matcher m = p.matcher(test);
    String result = "";
    while(m.find()){
        result = test.replaceAll("\\w*(lan)\\w+","<--->");
    }
    System.out.print(result);

结果是

plan <---> <---> <--->

我已经通过了 …