相关疑难解决方法(0)

我想通过Three.js中的IdMapping进行选择

由于性能问题,我只有一个巨大的几何体,计算如下:

for (var i = 0; i < numberOfVertices; i += 9) {
  p1  = new THREE.Vector3(graphData.triangles.vertices[i+0], graphData.triangles.vertices[i+1], graphData.triangles.vertices[i+2]);
  p2  = new THREE.Vector3(graphData.triangles.vertices[i+3], graphData.triangles.vertices[i+4], graphData.triangles.vertices[i+5]);
  p3  = new THREE.Vector3(graphData.triangles.vertices[i+6], graphData.triangles.vertices[i+7], graphData.triangles.vertices[i+8]);
  geometry.vertices.push(new THREE.Vertex( p1.clone() ));
  geometry.vertices.push(new THREE.Vertex( p2.clone() ));
  geometry.vertices.push(new THREE.Vertex( p3.clone() ));
  geometry.faces.push( new THREE.Face3( i/3, i/3+1, i/3+2 ) );

  // i want to do something like this:
  geometry.colors.push(new THREE.Color(0xFF0000));
  geometry.colors.push(new THREE.Color(0xFF0000));
  geometry.colors.push(new THREE.Color(0xFF0000)); 
}

geometry.computeFaceNormals();
var material = new THREE.MeshBasicMaterial({});

var triangles = new THREE.Mesh( geometry, material …