相关疑难解决方法(0)

urllib HTTPS请求:<urlopen error unknown url type:https>

我在python3.4上有一个脚本,直到我下载文件的网站决定使用https并且现在我收到错误但我无法弄清楚如何可以检索文件.

我的脚本导入以下库并使用urlretrive获取以前的文件.因为它现在转发到具有302重定向的https.我收到一些错误.

import urllib
import urllib.request

urllib.request.urlretrieve("http://wordpress.org/latest.tar.gz", "/thefile.gz")
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我的错误: -

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python3.4/urllib/request.py", line 178, in urlretrieve
    with contextlib.closing(urlopen(url, data)) as fp:
  File "/usr/local/lib/python3.4/urllib/request.py", line 153, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/local/lib/python3.4/urllib/request.py", line 461, in open
    response = meth(req, response)
  File "/usr/local/lib/python3.4/urllib/request.py", line 571, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/local/lib/python3.4/urllib/request.py", line 493, in error
    result = self._call_chain(*args)
  File "/usr/local/lib/python3.4/urllib/request.py", line 433, in _call_chain
    result …
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python python-3.4

11
推荐指数
1
解决办法
2万
查看次数

urllib.error.URLError:<urlopen error unknown url type:'https>

(Python 3.4.2)当我在脚本中运行'urllib.request.urlopen(url)'时,我遇到了一个奇怪的错误.如果我直接在Python解释器中运行它,它工作正常,但不是当我通过bash shell(Linux)在脚本中运行它时.

我猜它与'url'字符串有关,可能是因为我通过'string.join'方法创建字符串.

import urllib.request
url = "".join((baseurl, other_string, midurl, query))
response = urllib.request.urlopen(url)
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'url'字符串打印完美,但是当我尝试创建'response'字符串时,我得到了这个输出:

File "./script.py", line 124, in <module>
    response = urllib.request.urlopen(url)
  File "/usr/lib/python3.4/urllib/request.py", line 153, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib/python3.4/urllib/request.py", line 455, in open
    response = self._open(req, data)
  File "/usr/lib/python3.4/urllib/request.py", line 478, in _open
    'unknown_open', req)
  File "/usr/lib/python3.4/urllib/request.py", line 433, in _call_chain
    result = func(*args)
  File "/usr/lib/python3.4/urllib/request.py", line 1244, in unknown_open
    raise URLError('unknown url type: %s' % type)
urllib.error.URLError: <urlopen error unknown url …
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urllib python-3.x

7
推荐指数
1
解决办法
2万
查看次数

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