相关疑难解决方法(0)

我正在使用这些Scanner方法nextInt()并nextLine()阅读输入.

它看起来像这样:

System.out.println("Enter numerical value");    
int option;
option = input.nextInt(); // Read numerical value from input
System.out.println("Enter 1st string"); 
String string1 = input.nextLine(); // Read 1st string (this is skipped)
System.out.println("Enter 2nd string");
String string2 = input.nextLine(); // Read 2nd string (this appears right after reading numerical value)

问题是输入数值后,第一个input.nextLine()被跳过而第二个input.nextLine()被执行,所以我的输出如下所示:

Enter numerical value
3   // This is my input
Enter 1st string    // The program is supposed to stop here and …

所以我Scanner scan早先实例化了很多,但它在我的第二个scan.nextLine()之后跳过了scan.nextInt().我不明白为什么会跳过它？

     System.out.println("Something: ");

        String name = scan.nextLine();

        System.out.println("Something?: ");

        int number = scan.nextInt();

        System.out.println("Something?: ");

        String insurer = scan.nextLine();

        System.out.println("Something?: ");

        String another = scan.nextLine();