我的问题与 该线程中显式使用LambdaMetafactory密切相关,提供了一些非常好的例子来使用LambdaMetafactory访问类的静态方法; 但是,我想知道访问现有bean实例的非静态字段的等效代码是什么.似乎很难找到一个例子,我所执行的每一次尝试都以非工作代码结束.
这是bean代码:
class SimpleBean {
private Object obj= "myCustomObject";
private static Object STATIC_OBJECT = "myCustomStaticObject";
public Object getObj() {
return obj;
}
public void setObj(final Object obj) {
this.obj = obj;
}
public static Object getStaticObj() {
return STATIC_OBJECT;
}
public static void setStaticObj(final Object obj) {
STATIC_OBJECT = obj;
}
}
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这里是一个成功访问静态方法"getStaticObj()"的工作单元测试:
@Test
public void accessStaticMethod() throws Throwable
{
MethodHandles.Lookup caller = MethodHandles.lookup();
Method reflected = SimpleBean.class.getDeclaredMethod("getStaticObj");
MethodHandle methodHandle = caller.unreflect(reflected);
CallSite site = LambdaMetafactory.metafactory(caller, …Run Code Online (Sandbox Code Playgroud) 我试着做:
public class HelloWorld {
public static void main(String... args){
final String string = "a";
final Supplier<?> supplier = string::isEmpty;
System.out.println(supplier);
}
}
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我得到:
HelloWorld$$Lambda$1/471910020@548c4f57
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我想拿线isEmpty。我怎样才能做到这一点?
编辑:我创建的方法的代码是此之一:
public class EnumHelper {
private final static String values = "values";
private final static String errorTpl = "Can't find element with value `{0}` for enum {1} using getter {2}()";
public static <T extends Enum<T>, U> T getFromValue(T enumT, U value, String getter) {
@SuppressWarnings("unchecked")
final T[] elements = (T[]) ReflectionHelper.callMethod(enumT, values); …Run Code Online (Sandbox Code Playgroud) 我想在Java 8中创建一个lambda函数,获取它的类名,然后再从它的类名实例化该函数.
这是我尝试的:
import java.util.function.Consumer;
public class SimpleLambda
{
public static void call(String aLambdaClassName, String aArg) throws Exception
{
Class<Consumer<String>> lClass = (Class<Consumer<String>>) Class.forName(aLambdaClassName);
Consumer<String> newlamba = lClass.newInstance();
newlamba.accept(aArg);
}
public static void main(String[] args) throws Exception
{
{
// Attempt with a static method as lambda
Consumer<String> lambda = Host::action;
String classname = lambda.getClass().getName();
call(classname, "Hello world");
}
{
// Attempt with a locally defined lambda
Consumer<String> lambda = (s) -> { System.out.println(s); };
String classname = lambda.getClass().getName();
call(classname, …Run Code Online (Sandbox Code Playgroud) 只是一个理论问题,我目前没有实际的用例.
假设我的API接受函数引用作为参数,我想通过'::'语法直接从代码中提取它,或者通过反射收集匹配函数,存储在某些Map中并有条件地调用.
有可能以编程方式转换method成Consumer<String>?
Map<String, Consumer<String>> consumers = new HashMap<>();
consumers.put("println", System.out::println);
Method method = PrintStream.class.getMethod("println", String.class);
consumers.put("println", makeFunctionReference(method));
...
myapi.feedInto(consumers.get(someInput.getConsumerId()));
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更新:
虽然目前提供的答案不满足于解决方案,但在得到关于LambdaMetaFactory我试图编译此代码的提示之后
public class TestImpl {
public static void FnForString(String arg) {}
}
public class Test {
void test() {
List<String> strings = new ArrayList<>();
Consumer<String> stringConsumer = TestImpl::FnForString;
strings.stream().forEach(stringConsumer);
strings.stream().forEach(TestImpl::FnForString);
stringConsumer.accept("test");
}
}
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在将只有Test类送入CFR反编译器后,我得到了以下内容:
public class Test {
void test() {
ArrayList strings = new ArrayList();
Consumer<String> stringConsumer =
(Consumer<String>)LambdaMetafactory.metafactory( …Run Code Online (Sandbox Code Playgroud)