我创建了一个PHP页面,它应该从数据库中选择两个名称并显示它们.
它只是说:
<?php mysqli_connect(localhost,tdoylex1_dork,dorkk,tdoylex1_dork);
$name1 = mysqli_query("SELECT name1 FROM users
ORDER BY RAND()
LIMIT 1");
$name2 = mysqli_query("SELECT name FROM users
ORDER BY RAND()
LIMIT 1");
?>
<title>DorkHub. The online name-rating website.</title>
<link rel="stylesheet" type="text/css" href="style.css">
<body bgcolor='EAEAEA'>
<center>
<div id='TITLE'>
<h2>DorkHub. The online name-rating website.</h2>
</div>
<p>
<br>
<h3><?php echo $name1; ?></h3><h4> against </h4><h3><?php echo $name1; ?></h3>
<br><br>
<h2 style='font-family:Arial, Helvetica, sans-serif;'>Who's sounds the dorkiest?</h2>
<br><br>
<div id='vote'>
<h3 id='done' style='margin-right: 10px'>VOTE FOR FIRST</h3><h3 id='done'>VOTE FOR LAST</h3>
我的代码是:
<?php …我是一名初学者,也是一名文凭学生...我使用localhost创建了数据库...我在查看我的数据库时遇到问题...请帮助我...我希望你能用完整的代码帮我...这是错误...
Warning: mysqli_select_db() expects exactly 2 parameters, 1 given in C:\xampp\htdocs\SLR\View S110 PC01.php on line 10
cannot select DB
这是我的代码......
<?php
$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="slr"; // Database name
$tbl_name="s110_pc01"; // Table name
// Connect to server and select databse.
mysqli_connect("$host", "$username", "$password")or die("cannot connect");
mysqli_select_db("$db_name")or die("cannot select DB");
$sql="SELECT * FROM $tbl_name";
$result=mysqli_query($sql);
$count=mysqli_num_rows($result);
?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td><form name="form1" method="post" action="">
<table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> …