相关疑难解决方法(0)

我目前正在使用GsonRequest发出其余的GET请求.不清楚PUT请求的用途,我需要通过整个JSon对象发送更新.Request对象将接受PUT,但我不确定如何放置预期的JSon对象.

这是我的json要PUT:

 {
   prop1 : true,
   prop2 : false,
   prop4 : true
 }

以下是它在apiary.io中的提交方式,例如:

  var xhr = new XMLHttpRequest();
  xhr.open('PUT', 'http://my.apiary.io/v1/records/{myid}.json');

    xhr.send("{\n    \"isEditable\": false,\n    \"isClosed\": true,\n        \"isAvail\": true\n}");

我不知道把JSON放在哪里.

谢谢

public class GsonRequest<T> extends Request<T> {

private final Gson gson ;
private final Class<T> clazz;
private final Map<String, String> headers;
private final Listener<T> listener;

public GsonRequest(int method, String url, Class<T> clazz, Map<String, String> headers,
        Listener<T> listener, ErrorListener errorListener) {
    super(method, url, errorListener);

    GsonBuilder gsonBuilder = new GsonBuilder();
    gsonBuilder.registerTypeAdapter(Timestamp.class, new TimestampDeserializer()); …

我正在使用Android Volley库发送POST请求.并POST请求

• 标题是 Content-Type:application/json
• 邮政机构是 Json String

但无论如何,我要改变它Volley Request Header,它总是被设定为Content-Type:text/html.这给了我400 Bad Request.这是我的课程POST请求Volley

public class GsonRequest<T> extends Request<T> {
private final Class<T> clazz;
private final Map<String, String> headers;
private final Listener<T> listener;
private Map<String, String> postParams;
private String postString = null;

/**
 * Make a GET request and return a parsed object from JSON.
 * 
 * @param url
 *            URL of the request to make
 * …