相关疑难解决方法(0)

我知道这里有很多关于这方面的话题.我也多次阅读文档,但我找不到将数据从活动传递到片段的最佳方法.

我希望能够使用带选项卡的滑动视图在两个不同的布局(列表和地图)中显示我的可搜索活动的结果.我必须将2个数据传递给片段:"currentLocation"是当前用户位置,"result"是对象列表.

我已经省略了代码的某些部分,以使其更容易理解.

SearchableActivity.java

public class SearchableActivity extends ActionBarActivity implements TabListener {

    List<PlaceModel> result = new ArrayList<PlaceModel>();
    private SearchView mSearchView;
    private String currentLocation;

    AppSectionsPagerAdapter mAppSectionsPagerAdapter;
        ViewPager mViewPager;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.activity_searchable);

    final ActionBar actionBar = getSupportActionBar();
    actionBar.setHomeButtonEnabled(true);
    actionBar.setNavigationMode(ActionBar.NAVIGATION_MODE_TABS);

    mAppSectionsPagerAdapter = new AppSectionsPagerAdapter(getSupportFragmentManager());

    mViewPager = (ViewPager) findViewById(R.id.pager);
    mViewPager.setAdapter(mAppSectionsPagerAdapter);
    mViewPager.setOnPageChangeListener(new ViewPager.SimpleOnPageChangeListener() {
        @Override
        public void onPageSelected(int position) {
            actionBar.setSelectedNavigationItem(position);
        }
    });

    actionBar.addTab(actionBar.newTab().setText("List").setTabListener(this));
    actionBar.addTab(actionBar.newTab().setText("Map").setTabListener(this));

    // get currentLocation here

    handleIntent(getIntent());
}

@Override
protected void onNewIntent(Intent intent) {
    handleIntent(intent); …