相关疑难解决方法(0)

正如标题所示,我的目标是能够发送一条推文script.gs.该推文将发布到我的Feed中,理想情况下我无需访问Twitter网站.

我写了两个主要功能来尝试这个:

script.gs

//post tweet
function oAuth() {
  var CONSUMER_KEY = "**********************";
  var CONSUMER_SECRET = "*************************************************";
  ScriptProperties.setProperty("TWITTER_CONSUMER_KEY", CONSUMER_KEY);
  ScriptProperties.setProperty("TWITTER_CONSUMER_SECRET", CONSUMER_SECRET);
  var oauthConfig = UrlFetchApp.addOAuthService("twitter");
  oauthConfig.setAccessTokenUrl("https://api.twitter.com/oauth/access_token");
  oauthConfig.setRequestTokenUrl("https://api.twitter.com/oauth/request_token");
  oauthConfig.setAuthorizationUrl("https://api.twitter.com/oauth/authorize");
  oauthConfig.setConsumerKey(ScriptProperties.getProperty("TWITTER_CONSUMER_KEY"));
  oauthConfig.setConsumerSecret(ScriptProperties.getProperty("TWITTER_CONSUMER_SECRET"));
  var options = {muteHttpExceptions: true,oAuthServiceName:'twitter',oAuthUseToken:'always'}
  var url = "https://api.twitter.com/1.1/statuses/user_timeline.json";
  var response = UrlFetchApp.fetch(url, options).getContentText();
  Logger.log(response);
}
function postTweet() {
  oAuth();
  Logger.log('oAuth complete');
  var status = "Tweet";
  var Roptions = {
    method: "post",
    oAuthServiceName: "twitter",
    oAuthUseToken: "always",
    status: status
  };
  var url = "https://api.twitter.com/1.1/statuses/update.json";
  Logger.log('begin post');
  var request = UrlFetchApp.fetch(url, …