我下面有一个标志枚举.
[Flags]
public enum FlagTest
{
None = 0x0,
Flag1 = 0x1,
Flag2 = 0x2,
Flag3 = 0x4
}
Run Code Online (Sandbox Code Playgroud)
我无法将if语句评估为true.
FlagTest testItem = FlagTest.Flag1 | FlagTest.Flag2;
if (testItem == FlagTest.Flag1)
{
// Do something,
// however This is never true.
}
Run Code Online (Sandbox Code Playgroud)
我怎样才能做到这一点?
我正在做一些速度测试,我注意到Enum.HasFlag比使用按位操作慢大约16倍.
有谁知道Enum.HasFlag的内部以及为什么它如此之慢?我的意思是两倍慢不会太糟糕但是当它慢了16倍时它会使该功能无法使用.
如果有人想知道,这是我用来测试其速度的代码.
using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
namespace app
{
public class Program
{
[Flags]
public enum Test
{
Flag1 = 1,
Flag2 = 2,
Flag3 = 4,
Flag4 = 8
}
static int num = 0;
static Random rand;
static void Main(string[] args)
{
int seed = (int)DateTime.UtcNow.Ticks;
var st1 = new SpeedTest(delegate
{
Test t = Test.Flag1;
t |= (Test)rand.Next(1, 9);
if (t.HasFlag(Test.Flag4))
num++;
});
var st2 = new SpeedTest(delegate
{
Test t = …Run Code Online (Sandbox Code Playgroud) 只是为了抛出一些代码
string answer = "hotel"
if (answer == "house"|| answer == "hotel" || answer =="appartment")
{
DoSomething()
}
Run Code Online (Sandbox Code Playgroud)
我想知道是否有某种方法可以缩短它
string answer = "hotel"
if (answer == "house"|| "hotel" || "appartment")
{
DoSomething()
}
Run Code Online (Sandbox Code Playgroud)
我知道switch语句
switch (answer)
{
case "house":
case "hotel":
case "appartment": DoSomething();
break;
default :DoNothing();
}
Run Code Online (Sandbox Code Playgroud)
我只是想知道是否有一些像我上面描述的语法糖.