相关疑难解决方法(0)

Swift中是否有flattenScala,Xtend,Groovy,Ruby和co？

var aofa = [[1,2,3],[4],[5,6,7,8,9]]
aofa.flatten() // shall deliver [1,2,3,4,5,6,7,8,9] 

当然我可以使用reduce,但那有点糟透了

var flattened = aofa.reduce(Int[]()){
    a,i in var b : Int[] = a
    b.extend(i)
    return b
}

let array1 = ["Albert","Bobby"]
let array2 = ["Charles", "David"]

如何合并两个数组以便输出 ["Albert", "Charles", "Bobby", "David"]

如何根据结构（名称）中的键合并两个（第一个和第二个）结构数组。合并时，如果该元素中的任何值发生更改，我需要用第二个数组元素替换第一个数组的现有元素。

struct Example: Codable {
    var name: String
    var dob: String
    var address: String
}

var first: [Example] = []
var second: [Example] = []

first.append(Example(name: "Arun", dob: "01-01-1994", address: "Tirupati"))
first.append(Example(name: "Balaji", dob: "01-01-1994", address: "Tirupati"))
first.append(Example(name: "Prasanth", dob: "01-01-1994", address: "Tirupati"))
    first.append(Example(name: "Satish", dob: "01-01-1994", address: "Tirupati"))


second.append(Example(name: "Arun", dob: "01-01-1994", address: "Kadapa"))
second.append(Example(name: "Balaji", dob: "01-01-1994", address: "Tirupati"))
second.append(Example(name: "Prasanth", dob: "01-01-1994", address: "Tirupati"))
second.append(Example(name: "Harsha", dob: "01-01-1994", address: "Tirupati"))

/*    let merged: [Example] = merge(first, second, …