我在进行以下测试时遇到此错误:
it('should call pauseAnimationInterval if in focus', inject(function(SearchBoxData, intervalManager, $timeout){
SearchBoxData.init_array = [];
SearchBoxData.inFocus = true;
SearchBoxData.init(intervalManager);
console.log(intervalManager.pauseTimeout);
console.log(intervalManager.pauseTimeoutTime);
console.log($timeout);
$timeout.flush(intervalManager.pauseTimeoutTime+1);
expect(rootScope.$broadcast).toHaveBeenCalledWith('onPauseInterval', intervalManager.loopIndex);
}));
Run Code Online (Sandbox Code Playgroud)
它打破$timeout.flush(intervalManager.pauseTimeoutTime+1);
$ timeout方法在intervalManager.pauseAnimationInterval()里面调用SearchBoxData.init(intervalManager):
intervalManager.pauseAnimationInterval = function (){
intervalManager.safeCancel(intervalManager.continueInterval);
intervalManager.safeCancel(intervalManager.initInterval);
intervalManager.initInterval = null;
intervalManager.continueInterval = null;
intervalManager.pauseTimeout = $timeout(function () {
if(intervalManager.inFocus === true){
intervalManager.loopIndex += 1;
if(intervalManager.loopIndex >= intervalManager.maxLoopIndex){
intervalManager.loopIndex = 0;
}
$rootScope.$broadcast("onPauseInterval", intervalManager.loopIndex);
intervalManager.continueAnimationInterval();
}else{
// Important condition: retry after the timeout if no focus
// main reason of …Run Code Online (Sandbox Code Playgroud)