这是我的JSON字符串:
{"attributes":[{"nm":"ACCOUNT","lv":[{"v":{"Id":null,"State":null},"vt":"java.util.Map","cn":1}],"vt":"java.util.Map","status":"SUCCESS","lmd":13585},{"nm":"PROFILE","lv":[{"v":{"Party":null,"Ads":null},"vt":"java.util.Map","cn":2}],"vt":"java.util.Map","status":"SUCCESS","lmd":41962}]}
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我需要将上面的JSON String转换为Pretty Print JSON Output(使用Jackson),如下所示:
{
"attributes": [
{
"nm": "ACCOUNT",
"lv": [
{
"v": {
"Id": null,
"State": null
},
"vt": "java.util.Map",
"cn": 1
}
],
"vt": "java.util.Map",
"status": "SUCCESS",
"lmd": 13585
},
{
"nm": "PROFILE
"lv": [
{
"v": {
"Party": null,
"Ads": null
},
"vt": "java.util.Map",
"cn": 2
}
],
"vt": "java.util.Map",
"status": "SUCCESS",
"lmd": 41962
}
]
}
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任何人都可以根据我上面的例子给我一个例子吗?如何实现这种情况?我知道有很多例子,但我无法正确理解这些例子.通过一个简单的例子可以获得任何帮助.
更新:
以下是我使用的代码:
ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.defaultPrettyPrintingWriter().writeValueAsString(jsonString));
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但这不适用于我需要输出的方式,如上所述.
这是我用于上述JSON的POJO:
public class UrlInfo implements …Run Code Online (Sandbox Code Playgroud) 我已经尝试了在Spring Boot 2.0.0.M5中自定义健康执行器的新方法,如下所述:https://spring.io/blog/2017/08/22/introducing-actuator-endpoints-in-spring- boot-2-0:
@Endpoint(id = "health")
public class HealthEndpoint {
@ReadOperation
public Health health() {
return new Health.Builder()
.up()
.withDetail("MyStatus", "is happy")
.build();
}
}
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但是,当我运行HTTP GET时localhost:port/application/health,我仍然获得标准的默认健康信息.我的代码完全被忽略了.
当我使用通过实现自定义健康信息的"传统方式"时HealthIndicator,它按预期工作,健康信息用给定的细节装饰:
@Component
public class MyHealthIndicator implements HealthIndicator {
@Override
public Health health() {
return new Health.Builder()
.up()
.withDetail("MyStatus 1.1", "is happy")
.withDetail("MyStatus 1.2", "is also happy")
.build();
}
}
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问题:我还应该配置和/或实施哪些@Endpoint(id = "health")解决方案?
我的目的不是创建一个定制的执行器myhealth,而是定制现有的health执行器.基于文档,我希望通过实现HealthIndicator获得相同的结果.我错在那个假设吗?
Maven配置pom.xml包含: …