相关疑难解决方法(0)

以下代码在第2行接收seg错误:

char *str = "string";
str[0] = 'z';  // could be also written as *str = 'z'
printf("%s\n", str);

虽然这非常有效:

char str[] = "string";
str[0] = 'z';
printf("%s\n", str);

经过MSVC和GCC测试.

可能重复:
C/C++ Char指针崩溃

char *p = "atl";
char c;
c = ++*p; //crashing here

为什么会崩溃？

我知道不应该为数据创建指针增量的内存.