我试图从网站获取JSON并在将其放入iOS视图之前解析它.
这是我的代码;
func startConnection(){
let urlPath: String = "http://binaenaleyh.net/dusor/"
var url: NSURL = NSURL(string: urlPath)
var request: NSURLRequest = NSURLRequest(URL: url)
var connection: NSURLConnection = NSURLConnection(request: request, delegate: self, startImmediately: false)
connection.start()
}
func connection(connection: NSURLConnection!, didReceiveData data: NSData!){
self.data.appendData(data)
}
func buttonAction(sender: UIButton!){
startConnection()
}
func connectionDidFinishLoading(connection: NSURLConnection!) {
var err: NSError
// throwing an error on the line below (can't figure out where the error message is)
var jsonResult: NSDictionary = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: nil) as NSDictionary …Run Code Online (Sandbox Code Playgroud) 我托管了一个WCF服务,我试图在iPhone应用程序中使用它作为JSON POST请求.我打算稍后使用JSON序列化程序,但这是我对请求的要求:
NSString *jsonRequest = @"{\"username\":\"user\",\"password\":\"letmein\"}";
NSLog(@"Request: %@", jsonRequest);
NSURL *url = [NSURL URLWithString:@"https://mydomain.com/Method/"];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url];
NSData *requestData = [NSData dataWithBytes:[jsonRequest UTF8String] length:[jsonRequest length]];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody: requestData];
[NSURLConnection connectionWithRequest:[request autorelease] delegate:self];
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在收到的数据中,我只是将其打印到控制台:
- (void) connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
{
NSMutableData *d = [[NSMutableData data] retain];
[d appendData:data];
NSString *a = [[NSString alloc] initWithData:d encoding:NSASCIIStringEncoding];
NSLog(@"Data: %@", a);
}
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在这个回复中,我得到了这样的信息:
Data: <?xml version="1.0" …Run Code Online (Sandbox Code Playgroud)